-0.0196x^2+1.37x=0

Solution for -0.0196x^2+1.37x=0 equation:

-0.0196x^2+1.37x=0

a = -0.0196; b = 1.37; c = 0;
Δ = b2-4ac
Δ = 1.372-4·(-0.0196)·0
Δ = 1.8769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.37)-\sqrt{1.8769}}{2*-0.0196}=\frac{-1.37-\sqrt{1.8769}}{-0.0392}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.37)+\sqrt{1.8769}}{2*-0.0196}=\frac{-1.37+\sqrt{1.8769}}{-0.0392}
$